Kinetic Energy
Energy possessed by an object's motion is kinetic energy.
Work must be done to set any object in motion, and any moving object can do work. Energy is the ability to do work and kinetic energy is the energy of motion. There are several forms of kinetic energy
 vibration  the energy due to vibration motion
 rotational  the energy due to rotational motion
 translational  the energy due to motion from one location to another
Energy has the same units as work and work is force times distance. One Joule is one Newton of force acting through one meter  Nm or Joule in SIunits. The Imperial units are footpound.
 1 ft lb = 1.356 N m (Joule)
Translational Kinetic Energy
Translational kinetic energy can be expressed as
E_{t} = 1/2 m v^{2 } (1)
where
E_{t} = kinetic translation energy (Joule, ft lb)
m = mass (kg, slugs)
v = velocity (m/s, ft/s)
 one slug = 32.1740 pounds (as mass)  lb_{m}
Rotational Kinetic Energy
Rotational kinetic energy can be expressed as
E_{r} = 1/2 I ω^{2 } (2)
where
E_{m} = kinetic rotation energy (Joule, ft lb)
I = moment of inertia  an object's resistance to changes in rotation direction (kg m^{2}, slug ft^{2})
ω = angular velocity (rad/s)
Example  Kinetic Energy in a Car
The kinetic energy of a car with mass of 1000 kg at speed 70 km/h can be calculated as
E_{t} = 1/2 (1000 kg) ((70 km/h) (1000 m/km) / (3600 s/h))^{2}
= 189043 Joule
The kinetic energy of the same car at speed 90 km/h can be expressed as
E_{t} = 1/2 (1000 kg) ((90 km/h) (1000 m/km) / (3600 s/h))^{2}
= 312500 Joule
Note!  when the speed of a car is increased with 28% (from 70 to 90 km/h)  the kinetic energy of the car is increased with 65% (from 189043 to 312500 J). This huge rise in kinetic energy must be absorbed by the safety construction of the car to provide the same protection in a crash  which is very hard to achieve. In a modern car it is possible to survive a crash at 70 km/h. A crash at 90 km/h is more likely fatal.
Download and print Kinetic Energy in a Moving Car chart
Example  Kinetic Energy in a Steel Cube moving on a Conveyor Belt
A steel cube with weight 500 lb_{} is moved on a conveyor belt with a speed of 9 ft/s. The steel cube mass can be calculated as
m = (500 lb_{}) / (32.1740 ft/s^{2})
= 15.54 slugs
The kinetic energy of the steel cube can be calculated as
E_{t} = 1/2 (15.54 slugs) (9 ft/s)^{2}
= 629 ft lbs
Example  Kinetic Energy in a Flywheel
A flywheel with Moment of Inertia I = 0.15 kg m^{2} is rotating with 1000 rpm (revolutions/min). The angular velocity can be calculated as
ω = (1000 revolutions/min) (0.01667 min/s) (2 π rad/revolution)
= 104 rad/s
The flywheel kinetic energy can be calculated
E_{r} = 1/2 (0.15 kg m^{2}) (104 rad/s)^{2 }
= 821 J
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