Cable Loads

The equations below can also be used for cables only loaded with their own weight as long as the sagging height (h) vs. length (L) ratio is below 0.1.

Uniformly Loaded Cables with Horizontal Loads

The cable follows the shape of a parable and the horizontal support forces can be calculated as

R_1x = R_2x

      = q L² / (8 h)                               (1)

where

R_1x = R_2x = horizontal support forces (lb, N) (equal to midspan lowest point tension in cable)

q = unit load (weight) on the cable (lb/ft, N/m)

L = cable span (ft, m)

h = cable sag (ft, m)

• mass and weight

The vertical support forces at the end of the cable can be calculated as

R_1y = R_2y

      = q L / 2                               (1a)

where

R_1y = R_2y = vertical support forces  (lb, N)

The resultant forces acting in the end supports - and in the direction of the cable close to the supports - can be calculated as

R₁ = R₂

     = (R_1x² + R_1y²)^0.5

     = (R_2x² + R_2y²)^0.5                               (1b)

where

R_1,2 = resultant force at the support (lb, N)

The angle θ can be calculated as

θ = tan^-1(R_1y / R_1x)

   = tan^-1(R_2y / R_2x)           (1c)

The length of the sagged cable can be approximated to

s = L + 8 h² / (3 L)                                 (1d)    

where

s = cable length (ft, m)

Note that the equation is not valid when h > L / 4.

• kip = 1000 lb
• klf = kip per linear foot

Uniformly Loaded Cables with Horizontal Loads - Calculator

q - uniform load (N/m, lb/ft)

L - length (m, ft)

h - sag (m, ft)

• Load Calculator!

R_12x (N, lb): 45
R_12y (N, lb): 60
R₁₂ (N, lb): 75
θ (degrees): 53.1
s (m, ft):

Example - Uniform Cable Load, Imperial units

A cable with length 100 ft and a sag 30 ft has a uniform load 850 lb/ft. The horizontal supports and mid-span cable forces can be calculated as

R_1x = R_2x

     = (850 lb/ft) (100 ft)² / (8 (30 ft))

     = 35417 lb 

The vertical forces at the supports can be calculated as

R_1y = R_2y

      = (850 lb/ft) (100 ft) / 2

      =  42500 lb

The resultant forces acting in the supports can be calculated as

R_1,2 = ((35417 lb)² + (42500 lb)²)^0.5    

      = 55323 lb

The angle θ can be calculated as

θ = tan^-1((42500 lb) / (35417 lb))

           = 50.2 ^o  

The length of the sagged cable can be approximated to

s = (100 ft) + 8 (30 ft)² / (3 (100 ft))

   = 124 ft

Example - Uniform Cable Load, SI units

A cable with length 30 m and a sag 10 m has a uniform load of 4 kN/m. The horizontal supports and mid-span cable forces can be calculated as

R_1x = R_2x

      = (4000 N/m) (30 m)² / (8 (10 m))

      = 45000 N

      = 45 kN 

The vertical support forces can be calculated as

R_1y = R_2y

      = (4000 N/m) (30 m) / 2

              =  60000 N

              = 60 kN

The angle θ can be calculated as

θ = tan^-1((60 kN) / (45 kN))

           = 53.1 ^o  

The resultant force acting in the supports can be calculated as

R_1,2 = ((45000 N)² + (60000 N)²)^0.5    

           = 75000 N

           = 75 kN

The length of the sagged cable can be approximated to

s = (30 m) + 8 (10 m)² / (3 (30 m))

   = 38.9 m

Example - Known Tension at the Supports - Calculate Sagging and Length of Cable 

For a 30 m long cable with uniform load 4 kN/m the resulting tension in the cable at the end supports are 100 kN.

The vertical forces in the supports can be calculated as

R_1y = R_2y

      = (4 kN/m) (30 m) / 2

              = 60 kN

The horizontal forces in the supports can be calculated as

R_1x = R_2x

      = ((100 kN)² - (60 kN)²)^0.5

               = 80 kN 

The angle θ can be calculated as

θ = tan^-1((60 kN) / (80 kN))

           = 36.9 ^o  

The sagging can be calculated by modifying eq.1 to

h = q L² / (8 R_1x)

           = (4 kN/m) (30 m)² / (8 (80 kN))

           = 5.6 m  

The length of the sagged cable can be estimated to

s = (30 m) + 8 (5.6 m)² / (3 (30 m))

   = 32.8 m

     

Uniformly Loaded Cables with Inclined Chords

Inclined Cable Calculator - with Uniform Horizontal Loads

The calculator below can be used for cables with inclined chords and uniformly loads. The calculator is based on an iterative algorithm where the parable shaped cable is adapted to span L, height h₁ and h₂ according the figure above. The parable equation estimated below can be used to replicate the shape in spreadsheets or CAD systems.

The horizontal support forces in x-direction can be calculated as

R_1x = R_2x

      = q a² / (2 h₁)  

      = q b² / (2 h₂)                            (2a)

If b > a the maximum forces in the cable and at support 1 and 2 can be calculated as

R₂ = (R_2x² + (q b)²)^0.5                   (2c)

R₁ = (R_1x² + (q a)²)^0.5                   (2d)

 - and the vertical forces at support 1 and 2 can be calculated as

R_2y = (R₂² - R_2x²)^0.5                    (2e)

R_1y = (R₁² - R_1x²)^0.5                    (2f)

The angles between the horizontal and resulting forces can be calculated as

θ₂ = cos^-1(R_2x / R₂)                    (2g)

θ₁ = cos^-1(R_1x / R₁)                   (2g)

The length of the sagged cable can be estimated as

s_b = b (1 + 2/3 (h₂ / b)²)             (2h)

s_a = a (1 + 2/3 (h₁ / a)²)             (2i)

s = s_a + s_b                                (2j)

Example - Inclined Cable with Uniform Load, SI units

A cable with span 30 m, length a = 7.2 m, length b = 22.8 m, sag h₁= 1 m and sag h₂ = 10 m has a uniform load of 4 kN/m.

The horizontal support forces can be calculated as

R_1x = R_2x

      = (4 kN/m) (30 m)² / (2 (((1 m))^0.5 + ((10 m))^0.5))

      = 104 kN    

The resulting support forces can be calculated as 

R₂ = ((103.9 kN)² + ((4 kN/m) (22.8 m))²)^0.5                 

     = 138 kN

R₁ = ((103.9 kN)² + ((4 kN/m) (7.2 m))²)^0.5                

    = 108 kN

The vertical forces in the supports can be calculated as

R_2y = ((138.2 kN)² - (103.9 kN)²)^0.5          

      =  91.2 kN       

R_1y = ((107.8 kN)² - (103.9 kN)²)^0.5      

      = 28.8 kN 

The angles between resulting and horizontal forces in support 1 and 2 can be calculated as

θ₂ = cos^-1((103.9 kN)/ (138.2 kN))

    = 41.3 ^o          

θ₁ = cos^-1((103.9 kN)/ (107.8 kN))       

    = 15.5 ^o  

The length of the sagged cable can be calculated as

s_b = (22.8 m) (1 + 2/3 ((10 m) / (22.8 m))²) 

    = 25.7 m          

s_a =  (7.2 m) (1 + 2/3 ((1 m) / (7.2 m))²)

    = 7.3 m          

s = (7.3 m) + (25.7 m )   

  = 33 m