The required air flow to remove moisture or water vapor production in a room can be calculated as
L = G / (xr - xm) (1)
L = required air flow (kg/h)
G = moisture or vapor production in the room (kg/h)
xr = humidity ratio in room air (kgH2O/kg dry air)
xm = humidity ratio in make-up air (kgH2O/kg dry air)
Example - Removing Moisture from a Room
Required air flow to keep a humidity ratio of 0.010 (kgH2O/kg dry air) in a room with input air humidity ratio of 0.001 (kgH2O/kg dry air) and vapor production 100 (kg/h) can be calculated as
L = (100 kg/h) / ((0.010 kgH2O/kg dry air) - (0.001 kgH2O/kg dry air))
= 11020 (kg/h)
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The mass of water vapor present in moist air - to the mass of dry air.
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