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# Required Air Flow to Remove Moisture

## Air flow required to remove vapor production from a room.

The required air flow to remove moisture or water vapor production in a room can be calculated as

L = G / (xr - xm)                                    (1)

where

L = required air flow (kg/h)

G = moisture or vapor production in the room (kg/h)

xr = humidity ratio in room air (kgH2O/kg dry air)

xm = humidity ratio in make-up air (kgH2O/kg dry air)

### Example - Removing Moisture from a Room

Required air flow to keep a humidity ratio of 0.010 (kgH2O/kg dry air) in a room with input air humidity ratio of 0.001 (kgH2O/kg dry air) and vapor production 100 (kg/h) can be calculated as

L = (100 kg/h) / ((0.010 kgH2O/kg dry air) - (0.001 kgH2O/kg dry air))

= 11020 (kg/h)

## Related Topics

• ### Ventilation

Systems for ventilation and air handling - air change rates, ducts and pressure drops, charts and diagrams and more.

## Related Documents

• ### Air - Humidity Ratio

The mass of water vapor present in moist air - to the mass of dry air.
• ### Air - Maximum Moisture Carrying Capacity

Maximum water content in humid air vs. temperature.
• ### Evaporation from a Water Surface

Evaporation of water from a water surface - like a swimming pool or an open tank - depends on water temperature, air temperature, air humidity and air velocity above the water surface - online calculator.

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## Citation

• The Engineering ToolBox (2010). Required Air Flow to Remove Moisture . [online] Available at: https://www.engineeringtoolbox.com/moisture-remove-room-air-flow-d_1636.html [Accessed Day Month Year].

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12.1.10