Wet Steam  Quality vs. Dryness Fractions
Introduction and definition of steam quality and dryness fraction including calculating wet steam enthalpy and specific volume.
The steam dryness fraction is used to quantify the amount of water within steam.
 Dry steam  all water molecules are in the gaseous state
 Wet steam  a portion of the water molecules have lost their energy  latent heat  and condensed to tiny water droplets
To produce 100% dry steam in an boiler and keep the steam dry throughout the piping system is in general not possible. Droplets of water will escape from the boiler surface due to turbulence and splashing when bubbles of steam break through the water surface. The steam leaving the boiler space will contain a mixture of water droplets and steam.
In addition heat loss in the pipe lines condensates parts of the steam to droplets of water.
Steam  produced in a boiler where the heat is supplied to the water and where the steam is in contact with the water surface of the boiler  contains approximately 5% water by mass.
Dryness fraction of Wet Steam
If the water content in the steam is 5% by mass, then the steam is said to be 95% dry with a dryness fraction 0.95.
Dryness fraction can be expressed:
ζ = w_{s} / (w_{w} + w_{s}) (1)
where
ζ = dryness fraction
w_{w} = mass of water (kg, lb)
w_{s} = mass of steam (kg, lb)
Enthalpy of Wet Steam
Actual enthalpy of wet steam can be calculated with the dryness fraction  ζ  and the specific enthalpy  h_{s}  of "dry" steam picked from steam tables. Wet steam will always have lower usable heat energy than "dry" steam.
h_{t} = h_{s} ζ + (1  ζ ) h_{w} (2)
where
h_{t} = enthalpy of wet steam (kJ/kg, Btu/lb)
h_{s} = enthalpy of "dry" steam (kJ/kg, Btu/lb)
h_{w} = enthalpy of saturated water or condensate (kJ/kg, Btu/lb)
Specific Volume of Wet Steam
The droplets of water in wet steam occupies a negligible space in the steam and the specific volume of wet steam will be reduced by the dryness fraction.
v_{t} = v_{s} ζ (3)
where
v_{t} = specific volume of wet steam (m^{3}/kg, ft^{3}/lb)
v_{s} = specific volume of the dry steam (m^{3}/kg, ft^{3}/lb)
Example  Enthalpy and Specific Volume of Wet Steam
Steam with pressure 5 bar gauge (6 bar abs) has a dryness fraction of 0.95. From the steam table
h_{s} = 2755.46 (kJ/kg)
h_{w} = 670.43 (kJ/kg)
The total enthalpy can be calculated:
h_{t} = (2755.46 kJ/kg) 0.95 + (1  0.95) (670.43 kJ/kg)
= 2651 kJ/kg
Specific volume can be calculated:
v = (0.315 m^{3}/kg) 0.95
= 0.299 m^{3}/kg
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