Melting point is mainly a parameter that is needed for predicting solid-liquid phase behavior, especially for waxy oils. Equations developed by Riazi and Sahhaf for various homologous hydrocarbon groups can be used to estimate melting or freezing point of pure hydrocarbons with good accuracy (error of 1-1.5%) for practical calculations:
T MP = Melting point of n-alkanes (paraffins) in the carbon ranges of C 5 - C 40 , in Kelvin [K]
T MCP = Melting point of n-alkycyclopentanes (naphthenes) in the carbon ranges of C 7 - C 41 , in Kelvin [K]
T MCH = Melting point of n-alkycyclohexanes (naphthenes) in the carbon ranges of C 7 - C 20 , in Kelvin [K]
T MA = Melting point of n-alkybenzenes (aromatics) in the carbon ranges of C 9 - C 42 , in Kelvin [K]
M = molecular weight (molar mass) of the actual substance [g/mol], [kg/kmol]
In fact, in wax precipitation linear hydrocarbons from C 1 to C 15 as well as aromatics are absent, therefore there is no need for the melting point of very light hydrocarbons. For mixtures of hydrocarbons, the average molecular weight can be used in the equations, and then the melting temperature must be considered as the average melting temperature of the mixture.
See also Physical data for hydrocarbons , Physical data for alcohols and carboxylic acids , Melting points of hydrocarbons, alcohols and acids , Physical data for organic nitrogen compounds , Physical data for organic sulfur compounds and Melting and Boiling Point, Density and Solubility in Water for Inorganic Compounds
The figure shows calculated melting points (°C and °F) for the different kinds of hydrocarbons at varying molecular weights, compared to measured values:
Example 1: Melting point of nonylcyclopentane, with bruttoformula C 14 H 28
The molecular weight of nonylcyclopentane is: M = 14*12.02[g/mol] + 28*1.008[g/mol] = 196.4[g/mol]
For a cyclopentane like this, equation (2) is used: T M (heptylcyclopentane) = 370 - exp(6.52504 - 0.04945*196.4 (2/3) ) = 242.1[K]
Converted to °C and °F : 242.1[K] - 273.2 = -31.1[°C] and -31.1[°C]*1.8 + 32 = -23.9[°F]
Listed, measured values of melting point of nonylcyclopentane is -29°C.
Example 2: Melting and freezing point of a hydrocarbon mixture
A wax consists of 65wt% n-alkanes with an average molweight of 420 g/mol, 10wt% alkanecyclopentanes with an average molweight of 405 g/mol and 25wt% alkanecyclohexanes with an average molweight of 430 g/mol. What will the melting and freezing point of this wax be?
First, the average melting/freezing point of each hydrocarbon group is calculated:
T M (n-alkanes) = 397 - exp(6.5096 - 0.14187*420 0.47 ) = 337.6[K] = 65[°C]
T M (alkanecycklopentanes) = 370 - exp(6.52504 - 0.04945*405 2/3 ) = 324.7[K] = 51[°C]
T M (alkanecyclohexanes) = 360 - exp(6.55942 - 0.04681*430 0.7 ) = 333 [K] = 60[°C]
Note: The average molecular weight of 430 g/mol corresponds to a carbon number of 29, and thus, it is outside the validity range of Eq.(3). However, it is not expected to give large errors.
Since this is a mixture of compounds, and the average melting/freezing point is calculated from average molecular weights, the real melting and freezing will occur over a temperature range.
The solid wax will start to melt somewhat below 51 °C during heating, and the liquid wax will start to freeze somewhat above 65 °C during cooling. How far from the given temperatures it melts or freezes will depend on the width of the molecular weight range of the wax.
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