dt = dissipation time (s)
The energy stored in a 10 μF capacitor charged to 230 V can be calculated as
W = 1/2 (10 10 -6 F) (230 V) 2
= 0.26 J
in theory - if this energy is dissipated within 5 μs the potential power generated can be calculated as
P = (0.26 Joules) / (5 10 -6 s)
= 52000 W
= 52 kW
Be aware that in any real circuit, discharge starts at a peak value and declines. The energy dissipated is a very rough average power over the discharge pulse.
The time to discharge a capacitor at constant power load can be expressed as
dt = 1/2 C (U s 2 - U f 2 ) / P (3)
dt = discharge time (s)
U s = start voltage (V)
U f = final voltage (V)
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