Air Conditioner Efficiency
The ratio between heat removed and power (watt) used  EER and SEER.
Equipment used in cooling systems in residential and small commercial buildings often express the cooling system efficiency in terms like
 EER  Energy Efficiency Ratio and/or
 SEER  Seasonal Energy Efficiency Ratio
For air conditioners in rooms it is common to use EER  Energy Efficiency Ratio .
For central air conditioner systems it is more common to use SEER  Seasonal Energy Efficiency Ratio.
These ratings are normally posted on the Energy Guide Label attached to all new air conditioners.
Some air conditioner manufacturers participates in the voluntary Energy Star labeling program where the Energy Star label indicates higher EER and SEER ratings.
EER  Energy Efficiency Ratio
EER is a measure of how efficient a cooling system operates in steady state (over time) when the outdoor temperature is at a specific level (outdoor conditions commonly used are 95 ^{o}F (35 ^{o}C) ).
 the higher EER  the more energy efficient is the system
EER can be calculated
EER = q _{ c } / E (1)
where
q _{ c } = output cooling energy (Btu)
E = input electrical energy consumption (watthours, Wh)
EER is common for room air conditioners ranging 5000  15000 Btu per hour (1.5 kW  4.5 kW) .
 1 Btu/h = 2.931x10^{4} kW = 0.0299 kpm/s = 0.252 kcal/h = 3.986x10^{4} hk = 3.939x10^{4} hp = 0.2163 ft lb/s
In mild climates air conditioners with EER of at least 9.0 should be selected. In hotter climates air conditioners with EER above 10 should be selected.
Note that EER is sometimes erroneous based on cooling power and electrical power consumption as
EER _{ power } = P _{ c } / P _{ w } (1b)
where
P _{ c } = output cooling power (Btu/h)
P _{ w } = input electrical power consumption (W)
SEER  Seasonal Energy Efficiency Ratio
SEER  Seasonal Energy Efficiency Ratio  can be calculated
SEER = Q _{ c } / E (2)
where
Q _{ c } = seasonal cooling energy (Btu)
E = seasonal electrical energy consumption (Wh)
SEER should be at least 10  there are units where SEER reach at least 17 .
Example  EER _{ power } vs. COP _{ }
A cooling unit operates at 1 ton cooling (1 ton/kW)  or 12000 Btu/h .
The Energy Efficiendy Ratio EER _{ power } can be calculated as
EER _{ power } = (12000 Btu/h) / (1000 W)
= 12
Coefficient of Performance  COP  can be calculated as
COP = P _{ c } / P _{ w } (3)
where
COP = Coefficient of Performance
P _{ c } = output cooling power (Btu/h, W)
P _{ w } = input electrical power consumption (Btu/h, W)
Since 1 kW = 3412 Btu/h  COP for 1 ton cooling can be calculated as
COP = (12000 Btu/h) / ((1 kW) (3412 Btu/h / kW)
= 3.52
A small cooling unit operating at 1 ton per kW (1000 watts) is equivalent to a COP of 3.52 or an EER _{ power } of 12 .
The relationship between EER _{ power } and COP can be expressed as
EER _{ power } = 12 / 3.52 COP
= 3.41 COP
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